How do I solve this force and acceleration problem, F= ma?

Question

In an emergency stop to avoid an accident, a shoulder strap seat belt holds a 60 kg passenger firmly in place. If the car were initially traveling at 90 km/h and came to a stop in 5.5 s along a straight, level road, what was the average force applied to the passenger by the seatbelt?

-I know the formula is Force = mass x acceleration

the mass is 66 kg, and the acceleration (90/5.5) is -16.36 m/s.

I think I messed up somewhere because F = (66)(16.36) is a huge number, 981.82, and it is incorrect in my web assignment. I am either not solving my acceleration correctly, not using the correct unit for mass, or possibly both.

Please help, much appreciated.

Answer 1

Well, state what you know first...

F = ma

m = 60 kg

a = 90 km/s (or 250 m/s, unless I used the wrong formula to get that...)

But then it comes to a stop in 5.5 s...

So, then would you have approx. 45.5 m/s acceleration.

Now plug those numbers in...

Hmmm... well, then I got 2,730 N.

I think I messed it up too... I hate physics...

Well, try it out or something, good luck with that!

Answer 2

F Ma Problems

Answer 3

First dont mix up the km/h and m/s

90 km/h = 25 m/s

25 m/s / 5.5 s = 4.54 m/s^2 = avg accel

F = ma = 60 kg * 4.54 m/s^2 = 272 N

Answer 4

by using fact the article has no acceleration, no stress is had to circulate it. If, somewhat of speed, you have been given the acceleration, you ought to truly plug in the numbers to come to a decision the stress. yet by using fact the information given means that it relatively is moving at a persevering with speed, no stress is needed.