work on isobaric process?

Question

Calculate the work done on/by the gas in this following process:
1.Isobaric expansion from volume 2*10^-3 m^3 to 4*10^-3 m^3 at P 1*10^5 Pa
2. Isobaric compression from volume 4*10^-3 m^3 to 2*10^-3 m^3 at P 3*10^5 Pa

Thank you for your help

Answer 1

An isobaric process is a constant pressure process.



And the work performed is one of volumetric change at

constant pressure.



Therefore, W = P(V2-V1)



1. W = 10^5 ( 4 - 2)10^-3 = 200 J expansive work



2. W = 3(10^5)(2 - 4)10^-3 = - 600 J compressive work

Answer 2

Isobaric Process

Answer 3

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RE:

work on isobaric process?

Calculate the work done on/by the gas in this following process:

1.Isobaric expansion from volume 2*10^-3 m^3 to 4*10^-3 m^3 at P 1*10^5 Pa

2. Isobaric compression from volume 4*10^-3 m^3 to 2*10^-3 m^3 at P 3*10^5 Pa



Thank you for your help

Answer 4

Well!!!

The formula is Work Done = Pressure x Difference in Volume



1. W = 1*10^5 * (4-2)* 10^-3 = 200 J.. Work done by the gas = 200 J

2. W = 3*10^5 * (2-4)* 10^-3 = -600 J.. Work done on the gas = 600 J

Answer 5

in an isobaric process the pressure exerted by the system is constant throughout. There would be no change in pressure exerted whatsoever. Initial and final pressure exerted by the system would be same...A1 consider for example, there is temperature increase. the volume would have to be increased proportionately to maintain the constant pressure. probable misconception: you think that volume can change only due to pressure change.

Answer 6

P*(V2-V1)

positive answer implies by the gas. Else on the gas.