Question:
Find the angular frequency omega.
Martin Jessen
2008-08-03 21:59:58 UTC
One end of a spring with spring constant k is attached to the wall. The other end is attached to a block of mass m. The block rests on a frictionless horizontal surface. The equilibrium position of the left side of the block is defined to be x = 0. The length of the relaxed spring is L.
http://session.masteringphysics.com/problemAsset/1008964/16/71086_a.jpg

The block is slowly pulled from its equilibrium position to some position x_init > 0 along the x axis. At time t=0 , the block is released with zero initial velocity.

It is known that a general solution for the position of a harmonic oscillator is

x(t) = C*cos(omega*t) S*sin(omega*t)
where C, S, and omega are constants.

http://session.masteringphysics.com/problemAsset/1008964/16/71086_b.jpg

Find the angular frequency omega.
Express your answer in terms of k and m.
Three answers:
lilbac2003
2008-08-03 22:32:49 UTC
omega = sqrt(k/m)
rogowski
2016-12-17 19:29:23 UTC
Find The Angular Frequency
anonymous
2015-08-07 09:13:42 UTC
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RE:

Find the angular frequency omega.

One end of a spring with spring constant k is attached to the wall. The other end is attached to a block of mass m. The block rests on a frictionless horizontal surface. The equilibrium position of the left side of the block is defined to be x = 0. The length of the relaxed spring is L....


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