Question:
If an object can travel 50,000 light years in 7 days, what is the speed of the object times the speed of light
warlord
2008-07-05 03:50:16 UTC
If an object can travel 50,000 light years in 7 days, what is the speed of the object times the speed of light? What calculations are used?
Seven answers:
anonymous
2008-07-05 04:41:43 UTC
1 Light year = 9461*10^9 Km = 9461*10^12 m

5000 Light year = 4.7305*10^20 m

7 days = 168 hours = 10080 minutes = 604800 seconds

v(speed) =4.7305*10^20 / 604800 = 7.8216*10^14 m/s

Since c ( light velocity in vacuum ) = 3*10^8 m/s

So v = 7.8216*10^14 c / 3*10^8 = 2607200 c m/s

VERY FAST!!
david h
2008-07-05 04:22:20 UTC
Assuming that the object can travel faster that the speed of light and ignoring relativity time distortion etc then

An object travelling at the speed of light will travel 7 light days in 7 days.

speed =distance/time

50,000 light years/7days divided by 7 light days/7days which is 50,000 years/7 days which is 50,000 x 52 times faster than the speed of light.
siangnet2005
2008-07-05 04:35:03 UTC
This is quite an interesting problem. At first it may sound impossible but we can always apply the concepts of special relativity, with the reference frame changed, i.e. 50000 light years from our reference frame, and 7 days for that object's frame of reference.

From time dilation, we have t=g to, where t is the time from our refrence frame,to is the time under reference frame of object(to=7/365 yr), and g is gamma=1/sqrt[1-(v/c)^2].

Here we assume that (v/c) is so close to unity that 1+(v/c)=2.

Then,gamma=1/sqrt[1-(v/c)^2]

=1/sqrt[(1+(v/c))(1-(v/c))]

=1/sqrt[2(1-(v/c))]

So,from our frame of reference, the object should take 50000 years to travel that far.Hence we get t=50000yr. From the equation above, we get g=t/to = 50000/(7/365) =2.61x10^6.

Hence,1/sqrt[2(1-(v/c))]=2.61x10^6

sqrt[2(1-(v/c))]=3.83x10^-7

2(1-(v/c)) = 1.468 x 10^-13

(v/c) = 1- (1.468 x 10^-13)/2

= 1 - 7.34x10^-14

v = 0.9999999999999266c #
?
2016-11-10 07:45:18 UTC
An merchandise can't bypass swifter than easy. Conceivably, there could be a wave that quickly. wherein case, at 2.7 x 10^9 c, it might bypass ninety 3 billion ly in 34.4 years. At 27 x 10^10 c, it might bypass ninety 3 billion ly in 3.40 4 years. there's a small minority of scientists who have faith the tension of gravity propagates a minimum of 20 billion cases swifter than easy. i in my view have faith the tension of gravity is carried by making use of dark skill, that's an ethereal tension waves, while easy is an ethereal shear wave, and count includes orbiting pairs or communities of shear waves. So your question isn't completely ridiculous. only exchange "merchandise" to "wave". P.S.: The time paradox applies purely to clocks moving swifter than easy. there is not any paradox linked with information travelling swifter than easy. even with the reality that, I doubt if there is any risk of conveying information on the cost of dark skill.
anonymous
2008-07-05 04:26:15 UTC
light year is the distance travelled by light in one year at a rate of 3X10^8 m/s.

ie, 1ly = 3X10^8 X 60 X 60 X 24 X 365 = 9.46 X10^15 m/s

Velocity of the object is the distance travelled by it in one second.

ie, velocity of the object = (50,000 X ly) / 3600X24X7 = 0.082ly
Account Cancled
2008-07-05 05:35:00 UTC
Speed = Distance divided by time
Oskar S
2008-07-05 03:58:28 UTC
Nothing can travel that fast. Nothing can travel faster than the speed of light, and it would take light 50000 years. So it's a nonsense question.


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