Support force (physics)?

Question

ok i know what it means but in my book it says that the support force must equal the weight of the object ( it is supporting of course )

now it used the example of a book on a table and how the table is the support force and blablabla...

now im wondering that the table (support force) is NOT the same weight as the book.... so why did the definition say EQUAL! to the weight of the object? Did it mean equal or more?

Answer 1

The weight of the object is the object's mass times gravity which is the force of gravity on the book. The table being the normal force, the force perpendicular to the force will be equal to the weight of the book. Fn-Fg=0

Answer 2

Support Force

Answer 3

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Hi Jenny The answer is YES. If the car is moving along a level road, it is not accelerating in the vertical direction. By N1, there isn't therefore a resultant force in this direction, so it's weight must be counteracted by a N3 reaction force in the form of the road pushing up on the car . If you drove the car off a cliff, this supporting force would disappear, so the car will accelerate downwards. One confusion which often occurs is in understanding the idea of equilibrium, ie when forces are balanced. This can mean that the object is stationary, this is referred to as static equilibrium. But it can also apply to a moving object, eg an object falling with terminal velocity, where it is then referred to as dynamic equilibrium. Hope this helps, and good luck with your Physics test! Robin

Answer 4

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RE:

Support force (physics)?

ok i know what it means but in my book it says that the support force must equal the weight of the object ( it is supporting of course )



now it used the example of a book on a table and how the table is the support force and blablabla...



now im wondering that the table (support force) is NOT...

Answer 5

Robin has a pretty good answer, except for: "it's weight must be counteracted by a N3 reaction force in the form of the road pushing up on the car" The car's weight certainly is counteracted by the normal force of the road pushing up on the car, but that is NOT a Newton's Third Law ("N3") reaction force to the weight. The fact that the normal force is equal and opposite the weight is a conclusion one comes to after applying Newton's Second Law, and realizing that the vertical acceleration is zero. Remember that Newton's Third Law action/reaction force pairs must be the same kind of force, and are always equal and opposite (i.e., half of a pair can't "disappear"). The N3 reaction force to the gravitational force of the Earth pulling down on the car, is the gravitational force of the car pulling up on the Earth. The N3 reaction force to the Earth pushing up on the car with a normal force, is the car pushing down on the Earth with a normal force. Note that when the car is driven over a cliff, *both* halves of the gravitational pair continue to exist, and *both* halves of the normal force pair disappear.