You have two equations here:
1. F=0.5kx (the equation of the spring)
But F=ma=mv/t
So, mv/t = 0.5kx
Or, x=mv/0.5tk
2. x=0.5 at^2 (the equation of the deceleration of the car)
Substitute a=v/t and rearrange this to: x=0.5(v/t) * t^2
Or, x = 0.5vt
Rearrange to: t=2x/v
Now, substitute for the "t" in the first equation with the 2x/v from the second equation:
x=mv / 0.5(2x/v) k
Or, x = mv^2/xk
Or, x^2 = mv^2/k
Now, this is good because we know everything on the right side of the equation. So,
x^2 = 1480(14.9)(14.9) / (1.14x10^7)
x^2 = 0.0288
Therefore, x = 0.17
You can substitute units in the equation to make sure the units work out right:
x^2 = mv^2/2k
Since m is in units of kg, v is in units of m/s, and k is in units of N/m of kg/s^2, substitute the units for m, v, and k:
units of x^2 = (kg)(m/s)^2 / kg/s^2
The kg's cancel, as do the s^2 units. This leaves:
units of x^2 = m^2
which means x is in meters, which is what we want. :-)