Three resistors, 12.4 Omega, 41.0 Omega, and R, are connected in series with a 24.0 V battery. The tot?

Question

Three resistors, 12.4 Omega, 41.0 Omega, and R$, are connected in series with a 24.0 V battery. The total current flowing through the battery is 0.100 A.
A) Calculate the value of resistance R.
B) Calculate the potential difference across the 12.4 Omega resistor
C) Calculate the potential difference across the 41.0 Omega resistor
D) Calculate the potential difference across R

Answer 1

Circuit:

----/\/\/\/\------/\/\/\/\------/\/\/\/\----

| 12.4 41.0 R$ |

| |

|------------------|i-|i---------------------|

24V



Given,

R1=12.4

R2=41.0

R3=?

E=24V

I=0.1A



Ohm's Law,

E=IR

=> E=I*(R1+R2+R3) (Coz Resistors in series)

=> 24=0.1*(12.4+41.0+R3)

=> 240=(53.4+R3)

=> R3=186.6

R=186.6 Omega



Ohm's Law,

V=IR; (i.e. p.d = current * resistance)

current flowing in each resistance is same and equal to 0.1 A

For R1 = 12.4,

=> V1 = 0.1*12.4 = 1.24V



For R2 = 41.0,

=> V2 = 0.1*41.0 = 4.1V



For R3 = 186.6,

=> V3 = 0.1*186.6 = 18.66V



To check your answer adding these three must give E, 1.24+4.1+18.66 = 24

Answer 2

A:

Total resistance(Ohms) = Voltage(Volts) / Current(Amps)

R = V / I

R = 24 / 0.1

R = 240 Omega



Resistance of a resistor in series = Total resistance - Resistance of the other resistors in that series

R3 = Rt - R2 - R1

R3 = 240 - 41 - 12.4

R3 = 186.6 Omega

A) Value of resistance R is 186.6 Omega



ABC:

Potential difference = Voltage

Voltage across a circuit is spread out depending on the resistance of the individual component.

(a 10 Omega resistor will have half the potential difference of a 20 Omega resistor if they are in the same circuit and in series)

To find out how much voltage each unit of resistance gets, we divide the Total Voltage by the Total resistance.

24 / 240 = 0.1

To find the potential difference across a resistor, we multiply its resistance by 0.1.

B) 12.4 * 0.1 = 1.24 V

C) 41.0 * 0.1 = 4.1 V

D) 186.6 * 0.1 = 18.66 V

Answer 3

a) equivalent resistance of sequence resistors is the sum of the resistors = 12.5 ok b) present day is voltage / resistance = 9/12.5 = 0.seventy two A c) Voltage throughout resistor is present day x resistance __ V (3 Ohm Resistor) = 0.seventy two x 3 = 2.sixteen V __ V (4 Ohm Resistor) = 0.seventy two x 4 = 2.88 V __ V (5.5 Ohm Resistor) = 0.seventy two x 5.5 = 3.ninety six V d) entire voltage drop is sum of guy or woman voltages = battery voltage = 9 V

Answer 4

a) Total resistance = (E/I) = 24/0.1, = 240Ω.

240 - (12.4 + 41) = R value of 186.6Ω.

b) E = (IR) = 0.1 x 12.4, = 1.24V.

c) (0.1 x 41) = 4.1V.

d) (0.1 x 186.6) = 18.66V.