A car travelling at 60km/h overtakes another..........?

Question

A car travelling at 60km/h overtakes another car travelling at 42km/h. Assuming each car to be 5m long, find the time taken during the overtake and the total road distance used for the overtake?

STEPS REQUIRED PLZ

use the concepts of motion

Answer 1

60-42 = 18km/h = 5m/s



s = ut+1/2 at^2 with a = 0



s = 10m (5m to catch up with other car, 5m to clear it)



10 = 5*t => t = 2s



to find road distance



s = ut



u = 60km/h = 16.7m/s



s = 16.7 *2 = 33.3m

Answer 2

Time to overtake is the period between the front of the 60km/h reaching the end of the other car and its end reaching front of other cart.Thus the 60km/h cart travels 5m more than the other car in the same time.

60km/h=100/6m/s

42km/h=70/6m/s

if the time required is t,

t x(100/6-70/6)=5

so, t=1sec

total road dstance used is distance travelled by the 42km/h car during overtake.

i.e 70/6m=11.67m

Answer 3

Speed of car A= 60 km/h = 16.6666667 m/s

Speed of car B= 42 km/h = 11.6666667 m/s



Difference in speed A-B= 5 m/s



Total distance travel to Overtake= 5+5= 10m



Total time taken to over take = 10/5 = 2 sec



Road Distance travelled by Car A during overtake= 33.333 m

Road Distance travelled by Car B during overtake= 23.333 m

Answer 4

first car travels at 60kmph i.e., 50/3 metres per second.

second car travels at 42kmph i.e., 35/3 meters per second.

length of the two cars is 5m(given)

the relative speed of the two cars travelling in the same direction is

(50/3)-(35/3)=(15/3)

which equals 5meters per second

now, relative distance travelled by the two cars is

(5+5)=10m

since the length of each car is 5m(given).

therefore the time of meeting of the two cars is (10/5)

i.e., relative distance divided by relative speed of the cars.

so the car wil overtake the other car in 2 seconds

then the distance travelled for overtaking is (2*5)=10m

(the product of relative time and relative speed).

solution:

time to overtaket:2s

distance for overtaking: 10m

Answer 5

Interesting thread!