What is the horizontal component of the force?

Question

My professor gave me an assignment and I'm stuck in this question.

A force of 15 N acts on a box as shown. What is the horizontal component of the force?
http://i49.tinypic.com/elckt3.png

Answer 1

Fx = Fcos60° = F/2 = 7.5 N

Answer 2

The horizontal component of the force is calculated by using the formula F*(cosx)

Here F is the magnitude of the force and x is the angle that the force makes with the horizontal axis which is 60 degrees in this case.

So the answer is 15cos60 = 15*(1/2) = 7.5

Answer 3

The resultant horizontal component is as follow F(resultant)=Fcosθ.



So 15 x cos60= 15x0.5 = 7.5N.



Hope that helps :)!



It's simply a case of knowing that you take the cos of the angle and times that by the force which is acting upon the body!