calculate the index of refraction of the substance?

Question

The critical angle for total internal reflection for sapphire surrounded by air is 34.4°. Calculate the index of refraction of the substance.

Answer 1

n1 sin i = n2 sin r



in this case, n2 is air, so = 1 and sin r = 90, as the ray was totally internally reflected.



We have-:



n1 sin 34.4 = n2 sin 90



n1 sin 34.4 = 1



n1 = 1 / sin 34.4 = 1.77

Answer 2

Calculate Index Of Refraction

Answer 3

By Snell's Law;

µ1*sin i=µ2*sin r

here µ1=refractive index of sapphire

µ1=1*sin 90°/sin 34.4°

µ1=1.77

That's it......................



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U WOULD HAVE EASILY DONE IT IN THE TIME YOU POSTED IT HERE..