Question:
Relation between SHM and Wave?
anonymous
1970-01-01 00:00:00 UTC
Relation between SHM and Wave?
Four answers:
?
2016-08-08 21:35:04 UTC
Despite the fact that water is commonly considered incompressable, it is not. It can be just difficult to compress. However down within the Mariana Trench, miles under the surface the place it is very cold, that water is denser than the water on the surface above. Verify this out: "The density of ocean water at the sea floor is ready 1027 kg/m3. The 2 main causes that impact density of ocean water are the temperature of the water and the salinity of the water. The density of ocean water always raises with decreasing temperature until the water freezes. Ocean water, with an average salinity of 35 psu, freezes at 28.5oF (-1.94oC). Increasing salinity additionally raises the density of sea water. " [See source.] Your query is doubtful: are you speakme about the transverse waves, which might be exclusively on the skin, or the sound waves, which might be compression waves, no longer transverse? If you're talking in regards to the floor, transverse waves, then, sure there is a relationship. The reason waves break as they arrive onto a seaside, for illustration, is considering that the bottoms of the waves are acted on by way of the friction of the shallowing ocean bottom and slowed down relative to the tops of the waves. For this reason, the faster tops wreck and tumble over, which is what the surfer dudes journey on. The proof on this case is in the surfing. If you are speaking in regards to the subsurface, compression sound waves, however, yes, there's a relationship. As one answerer stated, sound travels turbo in higher densities than in minimize densities. And, as you see from the cite, it's denser on ordinary at deeper depths in the water. The proof in this case is in SONAR, which takes the velocity gradients with depth into consideration when navigating round underwater limitations or browsing for submarines for illustration. The velocity differentials will also be so extreme that a SONAR echo will bend vastly and give misguided echo ranging results if the velocity variations are not taken into consideration. [See source.]
Pearlsawme
2012-12-27 08:40:10 UTC
What is the relation between SHM and Wave?



In a wave each particle may execute S.H.M. But it is not necessary that in all waves the particle must execute S.H.M



There are number of waves in which each particle is not in S.H.M



http://upload.wikimedia.org/wikipedia/commons/7/77/Waveforms.svg



Only sin and cosine waves are S.H.M



If displacement of a particle at any instant of time is a function of sine or cosine, then the motion is called S.H.M.



The definition of S.H.M is that the acceleration is directly proportional to the displacement from the mean position and is pointed toward the mean position.



In that case, x = A sin ωt or A cos ωt. And acceleration = - ω^2 x

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Steve4Physics
2012-12-25 11:46:37 UTC
Not in the order you asked...

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"why is Cos and Sin function used to represent a SHM eqn"



Imagine something performing SHM - e.g. a mass on a spring bouncing up and down.



The displacement is the vector which measures how far the mass is on either side of the central position. E.g. the mass might be 2.0cm to above the centre: displacement = +2.0cm. A short time later the mass might be 1.2cm below the centre: displacement = -1.2cm.



The displacement changes continuously in a repeating pattern. If you plot a graph of displacement against time, you get patterns like the 1st link (sine graph) or 2nd link (cosine graph). You can get patterns in-between these, but keep it simple and ignore these.



The graphs have equations. So you can have an equation to work out the displacement (x) at any time if you have some other information. The equation might be, for example

x = 3.0sin(5t)

or

x = 43.1cos(0.2t

The number in front of the 'sin' or 'cos' is the amplitude. The number before the ''t' is called the angular frequency.

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"Whats is the relation between SHM and Wave?

sumone said that each particle in Wave Do SHM.Is that true?"



Yes - they are corect (for a simple waves).



Imagine a transverse wave moves left to right. E.g waves on the surface of water. Each water particle actually moves up and down, following the same pattern as the motion of the mass mentioned above. So each water particle in a wave is performing SHM.

If you watch one of the red particles in the 3rd link, this should be clear.
gr8guy
2012-12-25 10:02:48 UTC
thats a very rough explanation, but will not cover all kinds of waves. wave is the propagation of a disturbance in a medium. in many practical examples, an SHM can be the source of this disturbance. but they are two different things really.

also SHM has to be either a sine or a cosine function, while a wave can be anything.


This content was originally posted on Y! Answers, a Q&A website that shut down in 2021.
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