How to calculate capacitance if a metal is inserted instead of a dielectric?

Question

This is a parallel plate capacitor. The distance from +Q to -Q plate is 5 cm. The metal slab takes 1 cm. There is 2 cm of vacuum between the metal slab and the plates. How do I calculate the capacitance for the metal section? I am sure metal is not a dielectric, so I can't use the dielectric constant. So far I calculated the Capacitance of the other two sections as C1 = e_0*A/d_1 and C2 = e_0*A/d_2.

Note: e is epsilon

Thanks for the help.

Answer 1

Take the metal slab as being a conductive section between two series capacitors. Thus the total capacitance is C = 1/[(1/C1) + (1/C2)].

Answer 2

I think I get what you are asking.

If you are saying the "metal slab" is inserted between the 2 plates leaving 2cm. vacuum dielectric on each side, you have effectively 2 capacitors in SERIES.

So if you have a figure for the capacitance between 1 plate and the "slab", halve it.

Answer 3

considering the fact which you probably did no longer coach how the capacitors have been linked, and which 2 factors you opt for to discover the capacitance. the terrific and hassle-free way is degree it with a capacitor tester,then evaluate the tip result with 2 capacitor fee.