Drops of rain fall perpendicular to the roof of a parked car during a rainstorm. The drops strike the roof wit?

Question

Drops of rain fall perpendicular to the roof of a parked car during a rainstorm. The drops strike the roof with a speed of 11 m/s, and the mass of rain per second striking the roof is 0.075 kg/s.
(a) Assuming the drops come to rest after striking the roof, find the average force exerted by the rain on the roof.

Answer 1

F = m a which has units of kgm/s^2



notice that if we multiply 11m/s x 0.075kg/s we have units also of kgm/s^2 and this product is the average force acting on the roof

Answer 2

It's inversely proportional to the amount of dirt on the roof of the car.

Answer 3

(11m/s)(.075kg/s)

.825kg*m/s^2=F

F=.825 N