Calculus based Physics help?

Question

Calculus based Physics help?

Answer 1

The total force on A is -Ma*g - Ffa + T All this must equal zero.



0 = -6*g - 50*µs + T → T = 6*9.8 + 50*.40 = 78.8 N



T = the weight of x, so the mass of x, Mx = T/g = 8.04 kg

Answer 2

draw a free-body diagram...



bloack A... has a Tension (T) force pointing upward, frictional force and weight (mg) point downward.



the applied Force Fa to the left and the normal force exerted on the block by the vertical surface.



Block X has T upward and weight downward,



since its on the verge of slipping, the acceleration equals to zero.



Block x:



T - m2g = m(0)



so T = m2g.



to find the mass of X we have to find the tension force.. so now we take a look at block A







Block A :



T - m1g - Fs = m (0)



T = m1g + Fs



substitute this in for T in the block X equation.



So m1g + Fs = m2g



m1g + usFn = m2g



the Fn equals to the applied force



so (6)(9.8) +( 0.4)(50)/ g = m2



= 8.04 kg round off to 8 !

Answer 3

Let the mass of X is m Kg

=>mg - T = 0 -----(i)

T - 6g - mu(s) x 50 = 0 ----(ii)

=>By putting the value of T from (i) in (ii) :-

=>mg - 6g - mu(s) x 50 = 0

=>m x 9.8 - 6 x 9.8 - 0.4 x 50 = 0

=>m = 8.04 = ~8 Kg

=>2nd option is correct.