Brewster's Angle?

Question

What would Brewster's angle be for reflections off the surface of water for a light that came from beneath the surface of the water?
What is the angle for TIR (total internal reflection)?
What is the Brewster's angle for a light that came from above the surface of the water?

(All I know is that at a Brewster's angle, the reflected ray and refracted ray are at 90 degrees to each other)

Thanks in advance!!

Answer 1

When light moves between two medium of differing refractive index, generally some of it is reflected at the boundary. At one particular angle of incidence, however, light with one particular polarization cannot be reflected. This angle of incidence is Brewster's angle, θ(B). The polarization that cannot be reflected at this angle is the one for which the electric field of the light waves lies in the same plane as the incident ray and the surface normal. Light with this polarization is said to be p-polarized, because it is parallel to the plane. Light with the perpendicular polarization is said to be s-polarized, from the German senkrecht—"perpendicular". When unpolarized light strikes a surface at Brewster's angle, the reflected light is always s-polarized.



For light traveling from water to air:



n(air) = 1.0, n(water) = 1.33



θ(B) = ArcTan(n(air)/n(water)) = ArcTan(1.0/1.33)



= 36.95°



Total Internal Reflection is given by:



θ = ArcSin(n(air)/n(water)) = ArcSin(1.0/1.33)



= 48.75°



For light traveling from air to water:



θ(B) = ArcTan(n(water)/n(air)) = ArcTan(1.33/1.0)



= 53.06°

Answer 2

Brewster's Angle

Answer 3

Brewster Angle

Answer 4

Brewster angle is just the angle such that when a perfectly polarized light hits the incident surface of a medium, there is no reflection, only transmission, when unpolarized light hits that same medium with the brewster angle, the light that reflects becomes perfectly polarized. This can be derived using snell's law, but I won't go through that and just tell you that the brewster angle can be calculated using this formula: brewster angle = arctan(n2/n1) where n2 is the second medium that the incident light is entering (glass) and n1 is the incident medium, which is air in this case.

Answer 5

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RE:

Brewster's Angle?

What would Brewster's angle be for reflections off the surface of water for a light that came from beneath the surface of the water?

What is the angle for TIR (total internal reflection)?

What is the Brewster's angle for a light that came from above the surface of the water?



(All I...