How do you plot an x versus t graph when given an equation such as: x=(6m/s)t + (-2m/s^2)t^2?

Question

I'm having trouble getting started. I feel like I know how to approach this problem but I'm brain dead at the moment.

Answer 1

ok.. the standard approach will be to first find out the value of x say at time instance of t=0, the above equation will give u the value of x as 0 too...now take the value of x as 0 this will give you an equation (6m/s)t +(-2m/s^2)t^2 = 0; this is a quadratic equation which gives two possible values of t -> t= 0 and t = 3s now if you observe the value of x turns to 0 at 2 instances of t, so now there must be a point when the graph makes a turn around and the slope is thus a zero i.e. it attains a maxima, differentiate the equation with respect to t i.e. dx/dt and the equate the result to find that instance of t .. it'll come to t= 3s/2 which is the point where the graph turns around. now... when the value of t tends to infinity then the (-2m/s^2)t^2 will always be negative so x will tend towards minus infinity similarly when value of t is negative and tends towards minus infinity the value of (-2m/s^2)t^2 will again be always negative and since it's the product of a square it's value will also tend towards minus infinity. since there is only one solution for the maxima of this equation the graph will slope towards minus infinity with increasing value of t after 3s and before t=0... even if t is between -1 and 0.

Answer 2

Make a table of values. Label the left column "t", and the right column "x". Fill in values for "t" - start at 0, then 1, 2, 3, etc. (try some negative values, too). Substitute each value of "t" into the equation, evaluate it, and record the resulting value of "x" in the right column next to the corresponding value of "t". When you've got several points, make up the graph with "t" on the horizontal axis and "x" on the vertical. Plot each pair of (t, x). If you are not sure about the shape of the line between the points you have, pick additional values for "t" in between the ones you have, evaluate for those, and plot them.

Answer 3

in case you rearrange to y = 3 - x/2 you aspects x as many acceptable values as you like. Say x = a million placed that fee in the recent equation to get a cost for y which may be 3 - a million/2 = 2 and a million/2. circulate alongside the x axis +a million and up the y axis 2.and a million/2 and placed a small go at that element Do as many factors as you sense comfortable with ( 3 or 4 ) and then connect the crosses at their centres with a right this moment line

Answer 4

wow im only in 10th grade dont ask me, but thx for the points

Answer 5

type it into a graphing calculator

Answer 6

Try carefully?

Answer 7

stop showing off.