Help me, Moment of inertia of a wheel?

Question

A wheel is formed from a hoop of mass 3.1 kg
and 6 equally spaced spokes each of mass
0.057 kg. The hoop's radius is the length of
0.31 m each spoke.
A) Determine the moment of inertia of the
wheel about an axis through its center and
perpendicular to the plane of the wheel.

B) Determine the moment of inertia of the wheel
about an axis through its rim and perpendicular to the plane of the wheel.

How do i solve it
I = M(R^2) wont do

Answer 1

Once you calculate A), B) follows from the parallel axis theorem.



To calculate moment of inertia in part A) you will need the above formula (I=MR^2) but only for the hoop part. Then you add the moments of inertia of all 6 spokes, where individual spoke has I = ... look it up!



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... I= 1/3 m L^2



you can find them all here:



http://en.wikipedia.org/wiki/List_of_moments_of_inertia



List_of_moments_of_inertia

Answer 2

Moment Of Inertia Wheel

Answer 3

This Site Might Help You.



RE:

Help me, Moment of inertia of a wheel?

A wheel is formed from a hoop of mass 3.1 kg

and 6 equally spaced spokes each of mass

0.057 kg. The hoop's radius is the length of

0.31 m each spoke.

A) Determine the moment of inertia of the

wheel about an axis through its center and

perpendicular to the plane of the wheel.



B)...

Answer 4

add up the individual moments to get he moment of the system



The hoop is m*r^2

3.1*0.31^2



Each spoke is

m*L^2/3

0.057*0.31^2/3





add them together



3.1*0.31^2+6*0.057*0.31^2/3

0.31



j

Answer 5

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Well!!!!! You need to use parallel and perpendicular axes theorems for that!!