You are referring to the same question of placing a small balloon inside a container, and air is being pumped out of the container such that the balloon increases in size.
Initially when the balloon is placed inside the container, both the pressure inside the balloon and inside the container are the same.
Now when air is being pumped out of the container, the pressure of the container begins to decrease (ie the pressure outside the balloon decreases). The pressure inside the balloon is now greater than outside, so this pressure begins to push on the balloon wall, causing the balloon to increase in size (and thus volume).
(This is according to Boyle's Law:
Pressure of gas is inversely proportional to its volume at constant temperature).
As the pressure within the container decreases further, than the volume of the balloon will increase further as well, causing more and more stretching on the rubber skin of the balloon.
Eventually, the rubber is stretch to breaking point, where it cannot be stretch any more and it will tear and burst, due to the greater pressure inside the balloon.
Hope that I have answered yr question and clear yr doubts.