How do i graph current versus voltage?

Question

I have to create a graph of current versus voltage that includes data from all the devices i tested.
ok. I tested 4 different things and got a current and voltage for each. some people from my class said i should do the volts in milivolts but they didn't want to help me so they said it quickly. I have 10 readings from a closed circuit, 10 from the circuit with reversed polarity (which i know to enter with a negative sign), 10 from a set-up with an LED light and 7 from one with a light bulb. How do i follow what the instructions (said at the beginning)? Do I combine all of these things in order to graph it or do i make individual graphs for each chart? If i combine it, how do i do that? I know this may be a lot but i will be truly grateful to anyone who can help me.

Answer 1

its immaterial whether you plot in volts or milli-volts, but if the reading are like < 2 volts (like 1.2x v) than use milli-volts. you can plot all these reading on same graph but be sure first to connect all points of readings from LED (whether polarity is positive or negative) in increasing order and after you have your Graph for LED mark it (LED), it would be a curve not a line. And now with bulb do the same thing connect bulb only points with each other and do not integrate it with LED graph (if they intersect at some point its ok, but do not intentionally join them). SO this way you would finally have 2 graphs on a single sheet one for bulb and one for LED. You can plot them on separate sheets (it would work just fine) but plotting on same sheet will help you in proving the different behavior for Diodes (LED) and Resistance (Bulb). and that ohms law i.e. V/I = R doesn't hold for diodes as their resistance varies with current and voltage so their plot is a curve which keeps changing their resistance (inclination of V/I curve is resistance) and one more thing V should be on Y- axis.

Answer 2

What you will see is that voltage on the reverse bias diode has no current or very very small as you raise the voltage. Don't go above the maximum reverse voltage of the diode. The diode with forward bias will not show any current until after the voltage goes above the PN-junction barrier voltage. This varies according to the color and technology of the LED. If you use blue it will be more, infra-red (longer wave length) will be smaller. So there will be a step where the current starts at some offset. The current will go up very fast after the step. Do not exceed the forward voltage drop across the diode.



The bulb current and voltage drop across the device is the same with either polarity. The current goes up with the voltage because the bulb behaves much like a resister. It probably is not linear because of a temperature coefficient but this should not matter with your precision. It should look like a line.



I would like to see both positive and negative voltage on one graph for each device.



Diode scale:

The scale is bounded by the maximum forward voltage and the maximum revers voltage. You want to capture the 1-4 volt step caused by the barrier junction.



The bulb is whatever the bulb is. 3 volt bulb would be +/- 3 volts to ground.

Answer 3

It relies upon at actual one of those lightbulb. often, electric powered a lot are defined as both resistive a lot or inductive a lot, each and every with a oftentimes function V-I habit. As continually, the devil is interior the information. on your particular get at the same time, it relies upon even if both meters of cord is instantly or coiled and, if coiled, what precisely is the coil and what surrounds the coil (vacuum, air, transformer metal, an severe magnetic container?).

Answer 4

you will be making 4 graphs, one for each thing.

vertical axis is y

horizontal is x

y = current

x = voltage

the axis of the graph separate the plus and minus values

do an image search on google for graph and see for yourself how graphs are created

you can do this !!!!!