a theif plans to steal a gold sphere with the radius pf 28.9cm. If the gold has a density of 19.3g/cm cube, wh?

Question

a theif plans to steal a gold sphere with the radius pf 28.9cm. If the gold has a density of 19.3g/cm cube, what is the mass of the sphere in pounds

Answer 1

Assuming you mean that the density is 19.3 g/cm³ (cm cubed)



Volume you can calculate from

sphere V = ⁴/₃πr³

multiply by the density to get mass in grams

convert that mass into pounds. 1 US pound = 454 grams.

Answer 2

assuming it extremely is a sturdy gold sphere, mass = density x quantity = 19.3g/cm^3 x (4/3 pi (28.9cm)^3) mass = a million.95x10^6g = 1950 kg no longer likely in any respect that he ought to hold this away

Answer 3

By V = 4/3πr^3 = 4/3 x 3.14 x (28.90)^3 = 101055.96 cm^3

=>By m = Vd = 101055.96 x 19.3 = 1950379.94 gm

As 453.59 gm = 1 pound

=>1950379.94 gm = 1950379.94/453.59 pound = 4299.87 pounds