Can a full rectification(4 diodes) be operated in open circuit condition in excess of its voltage rating?

Question

This question initally sounds silly, but the need for such an application became evident as a means for blocking an air core secondary secondaries AC currents; So that the full amperage through the primary circuits enabling an incandescent ferrite current by conversion of the outer alternating currents into a central DC one; employing rectifications of two interphasal voltage rise circuits as shown at http://www.youtube.com/watch?v=1RKZCPSvoQk Three series resonant pancake coils, sourced from 3 phase alternator with dual interphasal full wave rectifications between all three resonant voltage rises; with the ending ferrite as a DC load.
2.8 DCA & 3.6 DCA 3/8ths width ferrite incandescence with corresponding 3 phase AC inputs
TWO Secondary coils are between the three pancake ones. These generate a much higher voltage then the primary system does and can be used to "pre-heat" the ferrite sample by also incorporating dual rectifications on the much higher voltages those secondary LC loops achieve simply by turns ratio. Now it becomes necessary to use this higher voltage circuit intially to decrease the resistance of the ferrite load, so that when the actual higher amperage primary circuit is employed, less amperage need be applied, analogous to the switching of gears in a transmission. In this circumstance if the rectifications are placed ACROSS the secondary LC loops, disconnecting its output across the shared ferrite load will NOT disable the amperage in the secondary coils themselves as desired, so that the primary circuit can operate exlusively as the power input to the ferrite load. This desired effect may instead be obtained by placing the dual rectifications in SERIES, INSTEAD OF ACROSS the individual secondary LC loop circulations, in which case then disconnecting the common ferrite load will also disable the currents of its source. However now we find that even though the load has come open circuit, this in turn registers a higher DC voltage at the source. The rating for these full wave rectifications is 1000 volts. I would assume then that operating the rectification in open circuit with a voltage above the rating will destroy the components by over volting even though no current is being drawn.

Answer 1

Yes, running a rectifier significantly in excess of its rating will destroy it. The rating is a voltage that it is guaranteed to work at, at normal temperature, so there will be some leeway before the device actually breaks down.



This sounds to me like fruitloopery. I didn't watch the whole video, but the comments don't look encouraging.

Answer 2

No, you can not apply more than the rated voltage just because there is no load drawing a current. There is still a reverse voltage across each diode in turn that would cause failure.

(The only exception is if the rating is very conservative).

Answer 3

There is a reason they have a rating. guess why? You will over load them because they are not rated by the draw of currant but the amount allowed to present it's self. If you exceed that amount you will over load with out any load draw. Sounds like an electronic motor starter.

Answer 4

confident you need to use a schottky diode for opposite voltage protection. decide for the optimum accessible opposite breakdown voltage (area of 40-60 volts) for the present score and alertness accessible. case in point in vehicle purposes i could decide for larger voltage and cutting-edge rankings.