physics genius needed!!!! melting iceberg!!?

Question

Icebergs in the North Atlantic present hazards to shipping, causing the length of shipping routes to increase by about 30 percent during the iceberg season. Attempts to destroy icebergs include planting explosives, bombing, torpedoing, shelling, ramming, and painting with lampblack. Suppose that direct melting of the iceberg, by placing heat sources in the ice, is tried. How much heat is required to melt 10 percent of a 3.30×105 metric-ton iceberg? One metric ton is equal to 103 kg. Assume that the iceberg is at 0°C. (Note: To appreciate the magnitude of this energy, compare your answer to the Hiroshima atomic bomb which had an energy equivalent to about 15,000 tons of TNT, representing an energy of about 6.0×1013 J.)


if you could do this also check out:
http://answers.yahoo.com/question/index;_ylt=ArCjR81trugTUEyW7T4hJR_sy6IX;_ylv=3?qid=20090314110305AAlxxO3

http://answers.yahoo.com/question/index;_ylt=AginVcxbEFc.0q0D1VvoTwrsy6IX;_ylv=3?qid=20090314142105AAg83Dt

thanks in advance... 10 points per problem! start answering!! =)

Answer 1

Mass of 10% of iceberg

= 3.3*10^4 tons

= 3.3*10^7 kg



E

= mass*latent heat of fusion

= 3.3*10^7*334000

=1.1022*10^13



Comparing with the Hiroshima atomic bomb

1.1022*10^13/6*10^13 *100%

The energy required to melt 10% of the iceberg is 18.37% of the energy released in the Hiroshima atomic bomb.

Answer 2

m=3.30 x 10^5 x 103 x 10/100= 3.4 x 10^6 kg & latent heat of ice melting(l)=334 kJ/kg

Q=m x l = 3.4 x 10^6 x 3.34 x 10^5=1.14 x 10^12 J

Thus Q(TNT)/:Q(ice)=60:1.14=52.6:1

Answer 3

I think it depends