The following shows the force of gravity to be that of a particular from of energy - therefore a force.
First, we shall look at the c2 value ("c^2" being understood to represent that of mass acceleration by the force of gravity) on the surface of earth (R = 3,950 miles); then we shall consider Earth at its radius of (R = 0.717 miles). Now, to begin; earth mass, 5.98 x 10 24 kilograms, times that of the gravitational constant 6.6732 x 10 -11, shall give us 399,057,360,000,000 or 3.9905736 x 10 14. This is our (E) energy value ("E" being that of internal heat energy within the mass of our planet) as it exhibits its presence in three dimensions. Next, we need to convert 3,950 miles into meters so everything remains in the metric system of computation. So we multiply that number times l,609.26 to find the distance in meters for the 3,950 miles. This equals 6,356,577; which number we have to multiply times itself in order to find (R2). The radius number times itself becomes 40,406,071,000,000 or 4.0406071 x 10 13. This is our "m" mass number (completing the equation of c^2 = E/m). Now we divide the (E) energy relationship by that of (m) mass and we arrive at 399,057,360,000,000 divided by 40,406,071,000,000; which equals 9.876 meters. By multiplying 9.876 meters times 3.281 we arrive at the English measurement of 32.40 feet acceleration per second 3,950 miles from the center of our planet. At which location you are probably accelerating right now. Then at 0.717 miles from the center point of earth, mass is accelerating at 186,258.84 miles per second. This is almost the speed of light (at 0.716 miles from the center of our planet mass would exceed the speed of light).
There is at http://youtube.com "Successful Gravity Experiment" that shows this force being that of a particular form of energy. It's boring unless you have an interest in such things. http://360.yahoo.com/noddarc goes more into the easy abstract.